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X*5X=300
We move all terms to the left:
X*5X-(300)=0
Wy multiply elements
5X^2-300=0
a = 5; b = 0; c = -300;
Δ = b2-4ac
Δ = 02-4·5·(-300)
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*5}=\frac{0-20\sqrt{15}}{10} =-\frac{20\sqrt{15}}{10} =-2\sqrt{15} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*5}=\frac{0+20\sqrt{15}}{10} =\frac{20\sqrt{15}}{10} =2\sqrt{15} $
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