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X*X+10=50
We move all terms to the left:
X*X+10-(50)=0
We add all the numbers together, and all the variables
X*X-40=0
Wy multiply elements
X^2-40=0
a = 1; b = 0; c = -40;
Δ = b2-4ac
Δ = 02-4·1·(-40)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*1}=\frac{0-4\sqrt{10}}{2} =-\frac{4\sqrt{10}}{2} =-2\sqrt{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*1}=\frac{0+4\sqrt{10}}{2} =\frac{4\sqrt{10}}{2} =2\sqrt{10} $
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