X+(+1)+(x+2)+(x+3)=62

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Solution for X+(+1)+(x+2)+(x+3)=62 equation: 



X+(+1)+(X+2)+(X+3)=62

We move all terms to the left:

X+(+1)+(X+2)+(X+3)-(62)=0

determiningTheFunctionDomain
X+(X+2)+(X+3)-62+(+1)=0

We add all the numbers together, and all the variables

X+(X+2)+(X+3)-62+1=0

We add all the numbers together, and all the variables

X+(X+2)+(X+3)-61=0

We get rid of parentheses

X+X+X+2+3-61=0

We add all the numbers together, and all the variables

3X-56=0

We move all terms containing X to the left, all other terms to the right

3X=56

X=56/3

X=18+2/3

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