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X+(-2/5X)+12/5=3
We move all terms to the left:
X+(-2/5X)+12/5-(3)=0
Domain of the equation: 5X)!=0determiningTheFunctionDomain X+(-2/5X)-3+12/5=0
X!=0/1
X!=0
X∈R
We get rid of parentheses
X-2/5X-3+12/5=0
We calculate fractions
X-3=0
We move all terms containing X to the left, all other terms to the right
X=3
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