X+(1/4)x=35

Solution for X+(1/4)x=35 equation:

X+(1/4)X=35

We move all terms to the left:

X+(1/4)X-(35)=0


Domain of the equation: 4)X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X+(+1/4)X-35=0

We multiply parentheses

X^2+X-35=0

a = 1; b = 1; c = -35;
Δ = b2-4ac
Δ = 12-4·1·(-35)
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{141}}{2*1}=\frac{-1-\sqrt{141}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{141}}{2*1}=\frac{-1+\sqrt{141}}{2}
$