X+(10+3x)+2(10+3x)+2(10+3x)+10=x+(10+3x)=2(10+3x)+10

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Solution for X+(10+3x)+2(10+3x)+2(10+3x)+10=x+(10+3x)=2(10+3x)+10 equation:



X+(10+3X)+2(10+3X)+2(10+3X)+10=X+(10+3X)=2(10+3X)+10
We move all terms to the left:
X+(10+3X)+2(10+3X)+2(10+3X)+10-(X+(10+3X))=0
We add all the numbers together, and all the variables
X+(3X+10)+2(3X+10)+2(3X+10)-(X+(3X+10))+10=0
We multiply parentheses
X+(3X+10)+6X+6X-(X+(3X+10))+20+20+10=0
We get rid of parentheses
X+3X+6X+6X-(X+(3X+10))+10+20+20+10=0
We calculate terms in parentheses: -(X+(3X+10)), so:
X+(3X+10)
We get rid of parentheses
X+3X+10
We add all the numbers together, and all the variables
4X+10
Back to the equation:
-(4X+10)
We add all the numbers together, and all the variables
16X-(4X+10)+60=0
We get rid of parentheses
16X-4X-10+60=0
We add all the numbers together, and all the variables
12X+50=0
We move all terms containing X to the left, all other terms to the right
12X=-50
X=-50/12
X=-4+1/6

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