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X+(2/3)+3X=10
We move all terms to the left:
X+(2/3)+3X-(10)=0
determiningTheFunctionDomain X+3X-10+(2/3)=0
We add all the numbers together, and all the variables
X+3X-10+(+2/3)=0
We add all the numbers together, and all the variables
4X-10+(+2/3)=0
We get rid of parentheses
4X-10+2/3=0
We multiply all the terms by the denominator
4X*3+2-10*3=0
We add all the numbers together, and all the variables
4X*3-28=0
Wy multiply elements
12X-28=0
We move all terms containing X to the left, all other terms to the right
12X=28
X=28/12
X=2+1/3
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