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X+(2X+40)+(3X+-50)=15002
We move all terms to the left:
X+(2X+40)+(3X+-50)-(15002)=0
We add all the numbers together, and all the variables
X+(2X+40)+(3X-50)-15002=0
We get rid of parentheses
X+2X+3X+40-50-15002=0
We add all the numbers together, and all the variables
6X-15012=0
We move all terms containing X to the left, all other terms to the right
6X=15012
X=15012/6
X=2502
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