X+(2x+40)+(3x+50)=15002

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Solution for X+(2x+40)+(3x+50)=15002 equation: 



X+(2X+40)+(3X+50)=15002

We move all terms to the left:

X+(2X+40)+(3X+50)-(15002)=0

We get rid of parentheses

X+2X+3X+40+50-15002=0

We add all the numbers together, and all the variables

6X-14912=0

We move all terms containing X to the left, all other terms to the right

6X=14912

X=14912/6

X=2485+1/3

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