X+(3/4)x=42

Solution for X+(3/4)x=42 equation:

X+(3/4)X=42

We move all terms to the left:

X+(3/4)X-(42)=0


Domain of the equation: 4)X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X+(+3/4)X-42=0

We multiply parentheses

3X^2+X-42=0

a = 3; b = 1; c = -42;
Δ = b2-4ac
Δ = 12-4·3·(-42)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{505}}{2*3}=\frac{-1-\sqrt{505}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{505}}{2*3}=\frac{-1+\sqrt{505}}{6}
$