X+(3x+6)+(2x+4)+109+(3x)=540

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Solution for X+(3x+6)+(2x+4)+109+(3x)=540 equation: 



X+(3X+6)+(2X+4)+109+(3X)=540

We move all terms to the left:

X+(3X+6)+(2X+4)+109+(3X)-(540)=0

We add all the numbers together, and all the variables

4X+(3X+6)+(2X+4)-431=0

We get rid of parentheses

4X+3X+2X+6+4-431=0

We add all the numbers together, and all the variables

9X-421=0

We move all terms containing X to the left, all other terms to the right

9X=421

X=421/9

X=46+7/9

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