X+(3x+6)+(2x+4)+109+(3x)=540

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Solution for X+(3x+6)+(2x+4)+109+(3x)=540 equation:



X+(3X+6)+(2X+4)+109+(3X)=540
We move all terms to the left:
X+(3X+6)+(2X+4)+109+(3X)-(540)=0
We add all the numbers together, and all the variables
4X+(3X+6)+(2X+4)-431=0
We get rid of parentheses
4X+3X+2X+6+4-431=0
We add all the numbers together, and all the variables
9X-421=0
We move all terms containing X to the left, all other terms to the right
9X=421
X=421/9
X=46+7/9

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