X+(3x-20)+3x+(3x+5)=145

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Solution for X+(3x-20)+3x+(3x+5)=145 equation: 



X+(3X-20)+3X+(3X+5)=145

We move all terms to the left:

X+(3X-20)+3X+(3X+5)-(145)=0

We add all the numbers together, and all the variables

4X+(3X-20)+(3X+5)-145=0

We get rid of parentheses

4X+3X+3X-20+5-145=0

We add all the numbers together, and all the variables

10X-160=0

We move all terms containing X to the left, all other terms to the right

10X=160

X=160/10

X=16

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