X+(4/3x)=(7/2)

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Solution for X+(4/3x)=(7/2) equation: 



X+(4/3X)=(7/2)

We move all terms to the left:

X+(4/3X)-((7/2))=0



Domain of the equation: 3X)!=0

X!=0/1

X!=0

X∈R



We add all the numbers together, and all the variables

X+(+4/3X)-((+7/2))=0

We get rid of parentheses

X+4/3X-((+7/2))=0

We calculate fractions


X+()/6X^2+(-((+7*3X)/6X^2=0

We multiply all the terms by the denominator


X*6X^2+(-((+7*3X)+()=0



We calculate terms in parentheses: +(-((+7*3X)+(), so:

-((+7*3X)+(



Wy multiply elements

6X^3+(-((+7*3X)+()=0



We calculate terms in parentheses: +(-((+7*3X)+(), so:

-((+7*3X)+(



We do not support eXpression: X^3

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