X+(5x+5)x=4

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Solution for X+(5x+5)x=4 equation:



X+(5X+5)X=4
We move all terms to the left:
X+(5X+5)X-(4)=0
We multiply parentheses
5X^2+X+5X-4=0
We add all the numbers together, and all the variables
5X^2+6X-4=0
a = 5; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·5·(-4)
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{29}}{2*5}=\frac{-6-2\sqrt{29}}{10} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{29}}{2*5}=\frac{-6+2\sqrt{29}}{10} $

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