X+(x+1)+(x+2)x=3

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Solution for X+(x+1)+(x+2)x=3 equation:


Simplifying
X + (x + 1) + (x + 2) * x = 3

Reorder the terms:
X + (1 + x) + (x + 2) * x = 3

Remove parenthesis around (1 + x)
X + 1 + x + (x + 2) * x = 3

Reorder the terms:
X + 1 + x + (2 + x) * x = 3

Reorder the terms for easier multiplication:
X + 1 + x + x(2 + x) = 3
X + 1 + x + (2 * x + x * x) = 3
X + 1 + x + (2x + x2) = 3

Reorder the terms:
1 + X + x + 2x + x2 = 3

Combine like terms: x + 2x = 3x
1 + X + 3x + x2 = 3

Solving
1 + X + 3x + x2 = 3

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + X + 3x + -1 + x2 = 3 + -1

Reorder the terms:
1 + -1 + X + 3x + x2 = 3 + -1

Combine like terms: 1 + -1 = 0
0 + X + 3x + x2 = 3 + -1
X + 3x + x2 = 3 + -1

Combine like terms: 3 + -1 = 2
X + 3x + x2 = 2

Add '-3x' to each side of the equation.
X + 3x + -3x + x2 = 2 + -3x

Combine like terms: 3x + -3x = 0
X + 0 + x2 = 2 + -3x
X + x2 = 2 + -3x

Add '-1x2' to each side of the equation.
X + x2 + -1x2 = 2 + -3x + -1x2

Combine like terms: x2 + -1x2 = 0
X + 0 = 2 + -3x + -1x2
X = 2 + -3x + -1x2

Simplifying
X = 2 + -3x + -1x2

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