X+(x+1)+(x+3)=64

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Solution for X+(x+1)+(x+3)=64 equation:



X+(X+1)+(X+3)=64
We move all terms to the left:
X+(X+1)+(X+3)-(64)=0
We get rid of parentheses
X+X+X+1+3-64=0
We add all the numbers together, and all the variables
3X-60=0
We move all terms containing X to the left, all other terms to the right
3X=60
X=60/3
X=20

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