X+(x+1)+(x+3)=64

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Solution for X+(x+1)+(x+3)=64 equation: 



X+(X+1)+(X+3)=64

We move all terms to the left:

X+(X+1)+(X+3)-(64)=0

We get rid of parentheses

X+X+X+1+3-64=0

We add all the numbers together, and all the variables

3X-60=0

We move all terms containing X to the left, all other terms to the right

3X=60

X=60/3

X=20

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