X+(x+1)=3(x+2)-8

Solution for X+(x+1)=3(x+2)-8 equation:

Simplifying
X + (x + 1) = 3(x + 2) + -8

Reorder the terms:
X + (1 + x) = 3(x + 2) + -8

Remove parenthesis around (1 + x)
X + 1 + x = 3(x + 2) + -8

Reorder the terms:
1 + X + x = 3(x + 2) + -8

Reorder the terms:
1 + X + x = 3(2 + x) + -8
1 + X + x = (2 * 3 + x * 3) + -8
1 + X + x = (6 + 3x) + -8

Reorder the terms:
1 + X + x = 6 + -8 + 3x

Combine like terms: 6 + -8 = -2
1 + X + x = -2 + 3x

Solving
1 + X + x = -2 + 3x

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + X + -1 + x = -2 + -1 + 3x

Reorder the terms:
1 + -1 + X + x = -2 + -1 + 3x

Combine like terms: 1 + -1 = 0
0 + X + x = -2 + -1 + 3x
X + x = -2 + -1 + 3x

Combine like terms: -2 + -1 = -3
X + x = -3 + 3x

Add '-1x' to each side of the equation.
X + x + -1x = -3 + 3x + -1x

Combine like terms: x + -1x = 0
X + 0 = -3 + 3x + -1x
X = -3 + 3x + -1x

Combine like terms: 3x + -1x = 2x
X = -3 + 2x

Simplifying
X = -3 + 2x