X+(x+2)+3(x+2)=68

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Solution for X+(x+2)+3(x+2)=68 equation: 


Simplifying
X + (x + 2) + 3(x + 2) = 68

Reorder the terms:
X + (2 + x) + 3(x + 2) = 68

Remove parenthesis around (2 + x)
X + 2 + x + 3(x + 2) = 68

Reorder the terms:
X + 2 + x + 3(2 + x) = 68
X + 2 + x + (2 * 3 + x * 3) = 68
X + 2 + x + (6 + 3x) = 68

Reorder the terms:
2 + 6 + X + x + 3x = 68

Combine like terms: 2 + 6 = 8
8 + X + x + 3x = 68

Combine like terms: x + 3x = 4x
8 + X + 4x = 68

Solving
8 + X + 4x = 68

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + X + -8 + 4x = 68 + -8

Reorder the terms:
8 + -8 + X + 4x = 68 + -8

Combine like terms: 8 + -8 = 0
0 + X + 4x = 68 + -8
X + 4x = 68 + -8

Combine like terms: 68 + -8 = 60
X + 4x = 60

Add '-4x' to each side of the equation.
X + 4x + -4x = 60 + -4x

Combine like terms: 4x + -4x = 0
X + 0 = 60 + -4x
X = 60 + -4x

Simplifying
X = 60 + -4x

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