X+(x+2)+X+4=1202

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Solution for X+(x+2)+X+4=1202 equation: 



X+(X+2)+X+4=1202

We move all terms to the left:

X+(X+2)+X+4-(1202)=0

We add all the numbers together, and all the variables

2X+(X+2)-1198=0

We get rid of parentheses

2X+X+2-1198=0

We add all the numbers together, and all the variables

3X-1196=0

We move all terms containing X to the left, all other terms to the right

3X=1196

X=1196/3

X=398+2/3

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