X+(x+3)(-3)=x-3=2

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Solution for X+(x+3)(-3)=x-3=2 equation: 



X+(X+3)(-3)=X-3=2

We move all terms to the left:

X+(X+3)(-3)-(X-3)=0

We get rid of parentheses

X+(X+3)(-3)-X+3=0

We multiply parentheses ..

X+(-3X-9)-X+3=0

We add all the numbers together, and all the variables

(-3X-9)+3=0

We get rid of parentheses

-3X-9+3=0

We add all the numbers together, and all the variables

-3X-6=0

We move all terms containing X to the left, all other terms to the right

-3X=6

X=6/-3

X=-2

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