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X+(X+5)+1/2X=30
We move all terms to the left:
X+(X+5)+1/2X-(30)=0
Domain of the equation: 2X!=0We get rid of parentheses
X!=0/2
X!=0
X∈R
X+X+1/2X+5-30=0
We multiply all the terms by the denominator
X*2X+X*2X+5*2X-30*2X+1=0
Wy multiply elements
2X^2+2X^2+10X-60X+1=0
We add all the numbers together, and all the variables
4X^2-50X+1=0
a = 4; b = -50; c = +1;
Δ = b2-4ac
Δ = -502-4·4·1
Δ = 2484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2484}=\sqrt{36*69}=\sqrt{36}*\sqrt{69}=6\sqrt{69}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-6\sqrt{69}}{2*4}=\frac{50-6\sqrt{69}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+6\sqrt{69}}{2*4}=\frac{50+6\sqrt{69}}{8} $
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