X+(x-10)+3x=290

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Solution for X+(x-10)+3x=290 equation: 



X+(X-10)+3X=290

We move all terms to the left:

X+(X-10)+3X-(290)=0

We add all the numbers together, and all the variables

4X+(X-10)-290=0

We get rid of parentheses

4X+X-10-290=0

We add all the numbers together, and all the variables

5X-300=0

We move all terms containing X to the left, all other terms to the right

5X=300

X=300/5

X=60

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