X+(x-19)+(x-19)+23=125

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Solution for X+(x-19)+(x-19)+23=125 equation: 



X+(X-19)+(X-19)+23=125

We move all terms to the left:

X+(X-19)+(X-19)+23-(125)=0

We add all the numbers together, and all the variables

X+(X-19)+(X-19)-102=0

We get rid of parentheses

X+X+X-19-19-102=0

We add all the numbers together, and all the variables

3X-140=0

We move all terms containing X to the left, all other terms to the right

3X=140

X=140/3

X=46+2/3

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