X+.07x+.2x(x+.07)=39

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Solution for X+.07x+.2x(x+.07)=39 equation: 



X+.07X+.2X(X+.07)=39

We move all terms to the left:

X+.07X+.2X(X+.07)-(39)=0

We add all the numbers together, and all the variables

X+.07X+.2X(X+0.07)-39=0

We add all the numbers together, and all the variables

1.07X+.2X(X+0.07)-39=0

We multiply parentheses

X^2+1.07X+0.07X-39=0

We add all the numbers together, and all the variables

X^2+1.14X-39=0

a = 1; b = 1.14; c = -39;
Δ = b2-4ac
Δ = 1.142-4·1·(-39)
Δ = 157.2996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.14)-\sqrt{157.2996}}{2*1}=\frac{-1.14-\sqrt{157.2996}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.14)+\sqrt{157.2996}}{2*1}=\frac{-1.14+\sqrt{157.2996}}{2}
$

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