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X+1(3X-4)=X+2(3X-4)
We move all terms to the left:
X+1(3X-4)-(X+2(3X-4))=0
We calculate terms in parentheses: -(X+2(3X-4)), so:We get rid of parentheses
X+2(3X-4)
We multiply parentheses
X+6X-8
We add all the numbers together, and all the variables
7X-8
Back to the equation:
-(7X-8)
X+1(3X-4)-7X+8=0
We add all the numbers together, and all the variables
-6X+1(3X-4)+8=0
We move all terms containing X to the left, all other terms to the right
-6X+1(3X-4)=-8
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