X+1/3+x+2/4=x+3/2+(x+4)

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Solution for X+1/3+x+2/4=x+3/2+(x+4) equation: 



X+1/3+X+2/4=X+3/2+(X+4)

We move all terms to the left:

X+1/3+X+2/4-(X+3/2+(X+4))=0



Domain of the equation: 2+(X+4))!=0

We move all terms containing X to the left, all other terms to the right

(X+4))!=-2

X∈R



We add all the numbers together, and all the variables

2X-(X+3/2+(X+4))+1/3+2/4=0

We calculate fractions


2X+(-(X+3*3*4)/((X+4))*3*4+2)+((X+4))*4+1*2)/((X+4))*3*4+2)+((X+4))*3+2*2)/((X+4))*3*4+2)=0



We calculate terms in parentheses: +(-(X+3*3*4)/((X+4))*3*4+2), so:

-(X+3*3*4)/((X+4))*3*4+2

We add all the numbers together, and all the variables

-(X+36)/((X+4))*3*4+2

We multiply all the terms by the denominator


-(X+36)+2*((X+4))*3*4

We get rid of parentheses

-X+2*((X+4))*3*4-36

We add all the numbers together, and all the variables

-1X+2*((X+4))*3*4-36

Back to the equation:

+(-1X+2*((X+4))*3*4-36)



We calculate fractions

We do not support eXpression: X^3

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