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X+1/5X=20
We move all terms to the left:
X+1/5X-(20)=0
Domain of the equation: 5X!=0We multiply all the terms by the denominator
X!=0/5
X!=0
X∈R
X*5X-20*5X+1=0
Wy multiply elements
5X^2-100X+1=0
a = 5; b = -100; c = +1;
Δ = b2-4ac
Δ = -1002-4·5·1
Δ = 9980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9980}=\sqrt{4*2495}=\sqrt{4}*\sqrt{2495}=2\sqrt{2495}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-2\sqrt{2495}}{2*5}=\frac{100-2\sqrt{2495}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+2\sqrt{2495}}{2*5}=\frac{100+2\sqrt{2495}}{10} $
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