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X+1/7X=16
We move all terms to the left:
X+1/7X-(16)=0
Domain of the equation: 7X!=0We multiply all the terms by the denominator
X!=0/7
X!=0
X∈R
X*7X-16*7X+1=0
Wy multiply elements
7X^2-112X+1=0
a = 7; b = -112; c = +1;
Δ = b2-4ac
Δ = -1122-4·7·1
Δ = 12516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12516}=\sqrt{4*3129}=\sqrt{4}*\sqrt{3129}=2\sqrt{3129}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-2\sqrt{3129}}{2*7}=\frac{112-2\sqrt{3129}}{14} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+2\sqrt{3129}}{2*7}=\frac{112+2\sqrt{3129}}{14} $
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