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X+1/9X=4
We move all terms to the left:
X+1/9X-(4)=0
Domain of the equation: 9X!=0We multiply all the terms by the denominator
X!=0/9
X!=0
X∈R
X*9X-4*9X+1=0
Wy multiply elements
9X^2-36X+1=0
a = 9; b = -36; c = +1;
Δ = b2-4ac
Δ = -362-4·9·1
Δ = 1260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1260}=\sqrt{36*35}=\sqrt{36}*\sqrt{35}=6\sqrt{35}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{35}}{2*9}=\frac{36-6\sqrt{35}}{18} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{35}}{2*9}=\frac{36+6\sqrt{35}}{18} $
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