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X+10X^2=22
We move all terms to the left:
X+10X^2-(22)=0
a = 10; b = 1; c = -22;
Δ = b2-4ac
Δ = 12-4·10·(-22)
Δ = 881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{881}}{2*10}=\frac{-1-\sqrt{881}}{20} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{881}}{2*10}=\frac{-1+\sqrt{881}}{20} $
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