X+150=2(3x)+23

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Solution for X+150=2(3x)+23 equation: 



X+150=2(3X)+23

We move all terms to the left:

X+150-(2(3X)+23)=0

We get rid of parentheses

X-23X-23+150=0

We add all the numbers together, and all the variables

-22X+127=0

We move all terms containing X to the left, all other terms to the right

-22X=-127

X=-127/-22

X=5+17/22

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