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X+150=3/4X
We move all terms to the left:
X+150-(3/4X)=0
Domain of the equation: 4X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+3/4X)+150=0
We get rid of parentheses
X-3/4X+150=0
We multiply all the terms by the denominator
X*4X+150*4X-3=0
Wy multiply elements
4X^2+600X-3=0
a = 4; b = 600; c = -3;
Δ = b2-4ac
Δ = 6002-4·4·(-3)
Δ = 360048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360048}=\sqrt{16*22503}=\sqrt{16}*\sqrt{22503}=4\sqrt{22503}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-4\sqrt{22503}}{2*4}=\frac{-600-4\sqrt{22503}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+4\sqrt{22503}}{2*4}=\frac{-600+4\sqrt{22503}}{8} $
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