X+2(x+1)+3(8+2)=4(x+3)

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Solution for X+2(x+1)+3(8+2)=4(x+3) equation: 



X+2(X+1)+3(8+2)=4(X+3)

We move all terms to the left:

X+2(X+1)+3(8+2)-(4(X+3))=0

We add all the numbers together, and all the variables

X+2(X+1)-(4(X+3))+310=0

We multiply parentheses

X+2X-(4(X+3))+2+310=0



We calculate terms in parentheses: -(4(X+3)), so:

4(X+3)

We multiply parentheses

4X+12

Back to the equation:

-(4X+12)



We add all the numbers together, and all the variables

3X-(4X+12)+312=0

We get rid of parentheses

3X-4X-12+312=0

We add all the numbers together, and all the variables

-1X+300=0

We move all terms containing X to the left, all other terms to the right

-X=-300

X=-300/-1

X=+300

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