X+2(x+1)-3(x+2)+4(x+3)=6(x+4)

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Solution for X+2(x+1)-3(x+2)+4(x+3)=6(x+4) equation: 



X+2(X+1)-3(X+2)+4(X+3)=6(X+4)

We move all terms to the left:

X+2(X+1)-3(X+2)+4(X+3)-(6(X+4))=0

We multiply parentheses

X+2X-3X+4X-(6(X+4))+2-6+12=0



We calculate terms in parentheses: -(6(X+4)), so:

6(X+4)

We multiply parentheses

6X+24

Back to the equation:

-(6X+24)



We add all the numbers together, and all the variables

4X-(6X+24)+8=0

We get rid of parentheses

4X-6X-24+8=0

We add all the numbers together, and all the variables

-2X-16=0

We move all terms containing X to the left, all other terms to the right

-2X=16

X=16/-2

X=-8

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