X+2(x-3)+4x-5=148

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Solution for X+2(x-3)+4x-5=148 equation: 



X+2(X-3)+4X-5=148

We move all terms to the left:

X+2(X-3)+4X-5-(148)=0

We add all the numbers together, and all the variables

5X+2(X-3)-153=0

We multiply parentheses

5X+2X-6-153=0

We add all the numbers together, and all the variables

7X-159=0

We move all terms containing X to the left, all other terms to the right

7X=159

X=159/7

X=22+5/7

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