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X+2(X-5)=2(X+1)
We move all terms to the left:
X+2(X-5)-(2(X+1))=0
We multiply parentheses
X+2X-(2(X+1))-10=0
We calculate terms in parentheses: -(2(X+1)), so:We add all the numbers together, and all the variables
2(X+1)
We multiply parentheses
2X+2
Back to the equation:
-(2X+2)
3X-(2X+2)-10=0
We get rid of parentheses
3X-2X-2-10=0
We add all the numbers together, and all the variables
X-12=0
We move all terms containing X to the left, all other terms to the right
X=12
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