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X+2/3X=5/3X
We move all terms to the left:
X+2/3X-(5/3X)=0
Domain of the equation: 3X!=0
X!=0/3
X!=0
X∈R
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X+2/3X-(+5/3X)=0
We get rid of parentheses
X+2/3X-5/3X=0
We multiply all the terms by the denominator
X*3X+2-5=0
We add all the numbers together, and all the variables
X*3X-3=0
Wy multiply elements
3X^2-3=0
a = 3; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·3·(-3)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*3}=\frac{-6}{6} =-1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*3}=\frac{6}{6} =1 $
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