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X+2/5X=-35
We move all terms to the left:
X+2/5X-(-35)=0
Domain of the equation: 5X!=0We add all the numbers together, and all the variables
X!=0/5
X!=0
X∈R
X+2/5X+35=0
We multiply all the terms by the denominator
X*5X+35*5X+2=0
Wy multiply elements
5X^2+175X+2=0
a = 5; b = 175; c = +2;
Δ = b2-4ac
Δ = 1752-4·5·2
Δ = 30585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(175)-\sqrt{30585}}{2*5}=\frac{-175-\sqrt{30585}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(175)+\sqrt{30585}}{2*5}=\frac{-175+\sqrt{30585}}{10} $
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