X+2/5x=140

Solution for X+2/5x=140 equation:

X+2/5X=140

We move all terms to the left:

X+2/5X-(140)=0


Domain of the equation: 5X!=0

X!=0/5

X!=0

X∈R


We multiply all the terms by the denominator


X*5X-140*5X+2=0

Wy multiply elements

5X^2-700X+2=0

a = 5; b = -700; c = +2;
Δ = b2-4ac
Δ = -7002-4·5·2
Δ = 489960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{489960}=\sqrt{36*13610}=\sqrt{36}*\sqrt{13610}=6\sqrt{13610}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-700)-6\sqrt{13610}}{2*5}=\frac{700-6\sqrt{13610}}{10}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-700)+6\sqrt{13610}}{2*5}=\frac{700+6\sqrt{13610}}{10}
$