X+2/5x=35

Solution for X+2/5x=35 equation:

X+2/5X=35

We move all terms to the left:

X+2/5X-(35)=0


Domain of the equation: 5X!=0

X!=0/5

X!=0

X∈R


We multiply all the terms by the denominator


X*5X-35*5X+2=0

Wy multiply elements

5X^2-175X+2=0

a = 5; b = -175; c = +2;
Δ = b2-4ac
Δ = -1752-4·5·2
Δ = 30585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-175)-\sqrt{30585}}{2*5}=\frac{175-\sqrt{30585}}{10}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-175)+\sqrt{30585}}{2*5}=\frac{175+\sqrt{30585}}{10}
$