X+20+2(x-10)+3/2=180

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Solution for X+20+2(x-10)+3/2=180 equation: 



X+20+2(X-10)+3/2=180

We move all terms to the left:

X+20+2(X-10)+3/2-(180)=0

determiningTheFunctionDomain
X+2(X-10)+20-180+3/2=0

We add all the numbers together, and all the variables

X+2(X-10)-160+3/2=0

We multiply parentheses

X+2X-20-160+3/2=0

We multiply all the terms by the denominator


X*2+2X*2+3-20*2-160*2=0

We add all the numbers together, and all the variables

X*2+2X*2-357=0

Wy multiply elements

2X+4X-357=0

We add all the numbers together, and all the variables

6X-357=0

We move all terms containing X to the left, all other terms to the right

6X=357

X=357/6

X=59+1/2

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