X+25/25=2/3x

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Solution for X+25/25=2/3x equation:



X+25/25=2/3X
We move all terms to the left:
X+25/25-(2/3X)=0
Domain of the equation: 3X)!=0
X!=0/1
X!=0
X∈R
We add all the numbers together, and all the variables
X-(+2/3X)+25/25=0
We add all the numbers together, and all the variables
X-(+2/3X)+1=0
We get rid of parentheses
X-2/3X+1=0
We multiply all the terms by the denominator
X*3X+1*3X-2=0
Wy multiply elements
3X^2+3X-2=0
a = 3; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·3·(-2)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{33}}{2*3}=\frac{-3-\sqrt{33}}{6} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{33}}{2*3}=\frac{-3+\sqrt{33}}{6} $

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