X+2=10/5x

Solution for X+2=10/5x equation:

X+2=10/5X

We move all terms to the left:

X+2-(10/5X)=0


Domain of the equation: 5X)!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X-(+10/5X)+2=0

We get rid of parentheses

X-10/5X+2=0

We multiply all the terms by the denominator


X*5X+2*5X-10=0

Wy multiply elements

5X^2+10X-10=0

a = 5; b = 10; c = -10;
Δ = b2-4ac
Δ = 102-4·5·(-10)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{3}}{2*5}=\frac{-10-10\sqrt{3}}{10}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{3}}{2*5}=\frac{-10+10\sqrt{3}}{10}
$