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X+2X(X+20)+120=360
We move all terms to the left:
X+2X(X+20)+120-(360)=0
We add all the numbers together, and all the variables
X+2X(X+20)-240=0
We multiply parentheses
2X^2+X+40X-240=0
We add all the numbers together, and all the variables
2X^2+41X-240=0
a = 2; b = 41; c = -240;
Δ = b2-4ac
Δ = 412-4·2·(-240)
Δ = 3601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{3601}}{2*2}=\frac{-41-\sqrt{3601}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{3601}}{2*2}=\frac{-41+\sqrt{3601}}{4} $
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