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X+3(2X+7)X=0
We multiply parentheses
6X^2+X+21X=0
We add all the numbers together, and all the variables
6X^2+22X=0
a = 6; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·6·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*6}=\frac{-44}{12} =-3+2/3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*6}=\frac{0}{12} =0 $
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