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X+3(X+1)=3-(2X+5)
We move all terms to the left:
X+3(X+1)-(3-(2X+5))=0
We multiply parentheses
X+3X-(3-(2X+5))+3=0
We calculate terms in parentheses: -(3-(2X+5)), so:We add all the numbers together, and all the variables
3-(2X+5)
determiningTheFunctionDomain -(2X+5)+3
We get rid of parentheses
-2X-5+3
We add all the numbers together, and all the variables
-2X-2
Back to the equation:
-(-2X-2)
4X-(-2X-2)+3=0
We get rid of parentheses
4X+2X+2+3=0
We add all the numbers together, and all the variables
6X+5=0
We move all terms containing X to the left, all other terms to the right
6X=-5
X=-5/6
X=-5/6
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