X+3+2+(5/7x)=24

Solution for X+3+2+(5/7x)=24 equation:

X+3+2+(5/7X)=24

We move all terms to the left:

X+3+2+(5/7X)-(24)=0


Domain of the equation: 7X)!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X+(+5/7X)+3+2-24=0

We add all the numbers together, and all the variables

X+(+5/7X)-19=0

We get rid of parentheses

X+5/7X-19=0

We multiply all the terms by the denominator


X*7X-19*7X+5=0

Wy multiply elements

7X^2-133X+5=0

a = 7; b = -133; c = +5;
Δ = b2-4ac
Δ = -1332-4·7·5
Δ = 17549
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-133)-\sqrt{17549}}{2*7}=\frac{133-\sqrt{17549}}{14}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-133)+\sqrt{17549}}{2*7}=\frac{133+\sqrt{17549}}{14}
$