X+3+2x+3=3(x+2)

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Solution for X+3+2x+3=3(x+2) equation: 



X+3+2X+3=3(X+2)

We move all terms to the left:

X+3+2X+3-(3(X+2))=0

We add all the numbers together, and all the variables

3X-(3(X+2))+6=0



We calculate terms in parentheses: -(3(X+2)), so:

3(X+2)

We multiply parentheses

3X+6

Back to the equation:

-(3X+6)



We get rid of parentheses

3X-3X-6+6=0

We add all the numbers together, and all the variables

=0

X=0/1

X=0

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