X+3+4(x-5)=48

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Solution for X+3+4(x-5)=48 equation: 



X+3+4(X-5)=48

We move all terms to the left:

X+3+4(X-5)-(48)=0

We add all the numbers together, and all the variables

X+4(X-5)-45=0

We multiply parentheses

X+4X-20-45=0

We add all the numbers together, and all the variables

5X-65=0

We move all terms containing X to the left, all other terms to the right

5X=65

X=65/5

X=13

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