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X+3/5=7/3(X+1)
We move all terms to the left:
X+3/5-(7/3(X+1))=0
Domain of the equation: 3(X+1))!=0We calculate fractions
X∈R
X+()/15X+(9XX/15X=0
We multiply all the terms by the denominator
X*15X+(9XX+()=0
We calculate terms in parentheses: +(9XX+(), so:Wy multiply elements
9XX+(
We add all the numbers together, and all the variables
9XX
Back to the equation:
+(9XX)
15X^2+9XX=0
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